Solution题目要求要求求出a1.b1.c1 a2.b2.c2的和其中0a10的7次方0b17, 0c19。代码如下//模拟#includeiostreamusing namespace std;inta1,b1,c1;//分别表示三位inta2,b2,c2;inta30,b30,c30;//结果intmain(){charch;cina1chb1chc1;cina2chb2chc2;intjw;//进位if(c1c229){c3c1c2-29;jw1;}else{c3c1c2;jw0;}if(b1b2jw17){b3b1b2jw-17;jw1;}else{b3b1b2jw;jw0;}a3a1a2jw;couta3.b3.c3;return0;}